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x^2-76x+400=0
a = 1; b = -76; c = +400;
Δ = b2-4ac
Δ = -762-4·1·400
Δ = 4176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4176}=\sqrt{144*29}=\sqrt{144}*\sqrt{29}=12\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-12\sqrt{29}}{2*1}=\frac{76-12\sqrt{29}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+12\sqrt{29}}{2*1}=\frac{76+12\sqrt{29}}{2} $
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